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diffraction & magnetic
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1. 我唔明佢21.1o個度即係點... That means the diffracted ray makes an angle of 21.1 degrees with the principal axis. (i) Let 入 be the longer wavelength. Because the two maxima produced by the two wavelengths are at the same angular position, we have, 3 x 424 = 2入 i.e. 入 = 636 nm (ii) Let a be the separation between two adjacent lines. a.sin(21.1) = 3 x 424 i.e. a = 3533 nm = 3.533 x 10^-6 m Hence, no. of lines per metre = 1/(3.533x10^-6) = 283,000 (iii) Let m be the order larger than 2 for the longer wavelength (636 nm) that overlapping occurs again. Hence, m(636) = (m+2).(424) (636 - 424)m = 848 m = 4 Therefore, 3533.sin(theta) = 4 x 636 i.e. angle(theta) = 46.06 degrees 2. There should be no electric field outside a current carrying wire if the current doesn't change with time By Faraday's Law, integral{ E.ds} = -d(phi)/dt [where "phi" represents the magnetic flux] But the magnetic flux surrounding a wire with steady current is constant, hence d(phi)/dt = 0, i.e. integral {E.ds} = 0 E = 0
其他解答:31C9A75CB3B14398
diffraction & magnetic
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我唔明佢21.1o個度即係點...1. A beam of light comprises two wavelengths is passed through a transmission diffraction grating. When viewed at an angle of 21.1o to the incident direction, the second order maximum for one wavelength is overlapped with the third order maximum for the other wavelength. The shorter wavelength is... 顯示更多 我唔明佢21.1o個度即係點... 1. A beam of light comprises two wavelengths is passed through a transmission diffraction grating. When viewed at an angle of 21.1o to the incident direction, the second order maximum for one wavelength is overlapped with the third order maximum for the other wavelength. The shorter wavelength is 424nm. i) Calculate the longer wavelength. (3M) ii) Determine the number of lines per metre in the diffraction grating. (2M) iii.) Determine the angle(s) (other than 21.1o) at which overlapping occur. (2M) 我估我識B dot ds個邊, 但E dot ds就唔知點搵... 2. Referring to the picture, two long wires carrying current I1 and I2 in opposite directions pass through a closed path S. http://postimg.org/image/jxbvfmra3/ Equations maybe related: http://postimg.org/image/ac2lyuz1v/最佳解答:
1. 我唔明佢21.1o個度即係點... That means the diffracted ray makes an angle of 21.1 degrees with the principal axis. (i) Let 入 be the longer wavelength. Because the two maxima produced by the two wavelengths are at the same angular position, we have, 3 x 424 = 2入 i.e. 入 = 636 nm (ii) Let a be the separation between two adjacent lines. a.sin(21.1) = 3 x 424 i.e. a = 3533 nm = 3.533 x 10^-6 m Hence, no. of lines per metre = 1/(3.533x10^-6) = 283,000 (iii) Let m be the order larger than 2 for the longer wavelength (636 nm) that overlapping occurs again. Hence, m(636) = (m+2).(424) (636 - 424)m = 848 m = 4 Therefore, 3533.sin(theta) = 4 x 636 i.e. angle(theta) = 46.06 degrees 2. There should be no electric field outside a current carrying wire if the current doesn't change with time By Faraday's Law, integral{ E.ds} = -d(phi)/dt [where "phi" represents the magnetic flux] But the magnetic flux surrounding a wire with steady current is constant, hence d(phi)/dt = 0, i.e. integral {E.ds} = 0 E = 0
其他解答:31C9A75CB3B14398
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