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dividing polynomials 2 --------urgent

發問:

1. (a^4 +a^2b^2 +b^4 ) / (a^2 + ab +b^2 ) (152b)<---no need to care about this2. (2a^3 +a^2 - 5a +2) / (a+1) (153b)3. (x^2 -3xy +2y^2 +3x - 6y -8) / (x-y+4) (153b)4. divide x^3 +4x^2 - 5x+3 by x-2 (154a)5. using the result of (4), write the... 顯示更多 1. (a^4 +a^2b^2 +b^4 ) / (a^2 + ab +b^2 ) (152b)<---no need to care about this 2. (2a^3 +a^2 - 5a +2) / (a+1) (153b) 3. (x^2 -3xy +2y^2 +3x - 6y -8) / (x-y+4) (153b) 4. divide x^3 +4x^2 - 5x+3 by x-2 (154a) 5. using the result of (4), write the relatioship between x^3 + 4x^2 -5x +3 and x-2 (154a) ( Ans. x^3 +4x^2 -5x +3 = ?????????????? )

最佳解答:

1. (a^4 +a^2b^2 +b^4 ) / (a^2 + ab +b^2 ) a^2 -ab + b^2 a^2+ab+b^2 | a^4 + a^2b^2 + b^4 a^4 + a^3b+a^2b^2 - a^3b + b^4 - a^3b - a^2b^2 - ab^3 a^2b^2 + ab^3 + b^4 a^2b^2 + ab^3 + b^4 So, the answer is (a^2 - ab + b^2) 2. (2a^3 +a^2 - 5a +2) / (a+1) If the dividing is a+1 , it will not complete to divided. So, it may be dividing a-1 2a^2 - a - 4 a + 1 | 2a^3 + a^2 -5a + 2 2a^3 + 2a^2 - a^2 - 5a + 2 - a^2 - a - 4a + 2 - 4a - 4 6 2a^2 + 3a - 2 a - 1 | 2a^3 + a^2 -5a + 2 2a^3 + 2a^2 3a^2 - 5a + 2 3a^2 - 3a - 2a + 2 - 2a + 2 So the answer will be (2a^2 - a - 4) and remind 6 or (2a^2 + 3a -2) 3. (x^2 -3xy +2y^2 +3x - 6y -8) / (x-y+4) x - 2y - 1 x - y + 4 | x^2 - 3xy + 2y^2 + 3x - 6y - 8 x^2 - xy + 4x - 2xy + 2y^2 -x -6y -8 - 2xy + 2y^2 - 8y -x + 2y - 8 -x + y - 4 y - 4 So the answer is (x-2y-1) and remind (y-4) 4. divide x^3 +4x^2 - 5x+3 by x-2 x^2 + 6x + 7 x - 2 | x^3 + 4x^2 - 5x + 3 x^3 - 2x^2 6x^2 - 5x + 3 6x^2 -12x 7x + 3 7x - 14 17 so the answer is (x^2 +6x + 7 ) and remind 17 5. using the result of (4), write the relatioship between x^3 + 4x^2 -5x +3 and x-2 x^3 +4x^2 -5x +3 = (x - 2)(x^2 +6x + 7 ) + 17

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