close
標題:

Physics F.3 Questions 20 pts.

發問:

Q.1) X , YTemp.: 2T , 5TMass: 3m , mHeat capacity : 2C , Ci)--ii) The two liquids are mixed together. Find the temp. of the mixture. Assume that no energy is lost to the surroundings. Express your answer in terms of T. ... 顯示更多 Q.1) X , Y Temp.: 2T , 5T Mass: 3m , m Heat capacity : 2C , C i)-- ii) The two liquids are mixed together. Find the temp. of the mixture. Assume that no energy is lost to the surroundings. Express your answer in terms of T. (Ans.:3T) iii) Then the mixture is heated so that its temperature reaches 5 T again. Find the engery absorbed by the mixture in terms of C and T. Q.2) Winnie buys an instantaneous heater of power 20000 W. Assume water flows at 0.2 kg per second in the heater and the initial temperature of water is 15℃. Find the temperature of water after heating. (Ans.: 38.8℃)

最佳解答:

aa.jpg

 

此文章來自奇摩知識+如有不便請留言告知

1.(ii) Heat lost by the liquid Y = m.C.(5T-T') where T' is the final temperature of the mixture Heat gained by the liquid X = 3m.2C.(T'-2T) Hence, m.C.(5T-T') = 3m.2C.(T'-2T) i.e. 5T-T' = 6(T'-2T) 7T' = 17T T' = (17/7)T (iii) Heat absorbed by liquid X = (3m).(2C).(5T-17T/7) = 15.43mCT Heat absorbed by liquid Y = m.C.(5T-17T/7) = 2.57mCT Hence, total nergy absorbed = (15.43+2.57)mCT = 18mCT 2. Let T be the final temperature of water 20000 = 0.2 x 4200 x (T-15) where 4200 J/kg-C is the specific heat capacity of water solve for T gives T = 38.8 degree C

其他解答:
arrow
arrow

    xvnjcke 發表在 痞客邦 留言(0) 人氣()