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唔識呀!!! help me pls!! 1. In each of the following, find the i) slope;ii) inclination, correct to the nearest 0.1^oof the straight line passing through the two given points.a) A (1, -3), B (5, 3)b) C (-4, -2), D (2, 0)2. It is given three points A (-3, 6), B (0, 1) and C (6, -9).a) Find the... 顯示更多 唔識呀!!! help me pls!! 1. In each of the following, find the i) slope; ii) inclination, correct to the nearest 0.1^o of the straight line passing through the two given points. a) A (1, -3), B (5, 3) b) C (-4, -2), D (2, 0) 2. It is given three points A (-3, 6), B (0, 1) and C (6, -9). a) Find the slopes of AB and BC b) Are the points A, B and C collinear (i.e. lie on the same straight line)?
最佳解答:
1.a) i) Slope of AB = (-3-3)/(1-5) = -6/-4 = 3/2 ii) Let θ be the inclination tan θ = 3/2 θ = 56.3?, cor. to the nearest 0.1? b) i) Slope of CD = (-2-0)/(-4-2) = 1/3 ii) Let θ be the inclination tan θ = 1/3 θ = 18.4 ?, cor. to the nearest 0.1? 2a) Slope of AB = (6-1)/(-3-0) = -5/3 Slope of BC = (-9-1)/(6-0) = -5/3 b) Slope of AB = Slope of BC points A,B and C are collinear. 2010-08-26 15:57:32 補充： 1a)ii) Hence the angle of inclination is 56.3 deg b)ii) Hence the angle of inclination is 18.4 deg
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coordinate geometry~~發問:
唔識呀!!! help me pls!! 1. In each of the following, find the i) slope;ii) inclination, correct to the nearest 0.1^oof the straight line passing through the two given points.a) A (1, -3), B (5, 3)b) C (-4, -2), D (2, 0)2. It is given three points A (-3, 6), B (0, 1) and C (6, -9).a) Find the... 顯示更多 唔識呀!!! help me pls!! 1. In each of the following, find the i) slope; ii) inclination, correct to the nearest 0.1^o of the straight line passing through the two given points. a) A (1, -3), B (5, 3) b) C (-4, -2), D (2, 0) 2. It is given three points A (-3, 6), B (0, 1) and C (6, -9). a) Find the slopes of AB and BC b) Are the points A, B and C collinear (i.e. lie on the same straight line)?
最佳解答:
1.a) i) Slope of AB = (-3-3)/(1-5) = -6/-4 = 3/2 ii) Let θ be the inclination tan θ = 3/2 θ = 56.3?, cor. to the nearest 0.1? b) i) Slope of CD = (-2-0)/(-4-2) = 1/3 ii) Let θ be the inclination tan θ = 1/3 θ = 18.4 ?, cor. to the nearest 0.1? 2a) Slope of AB = (6-1)/(-3-0) = -5/3 Slope of BC = (-9-1)/(6-0) = -5/3 b) Slope of AB = Slope of BC points A,B and C are collinear. 2010-08-26 15:57:32 補充： 1a)ii) Hence the angle of inclination is 56.3 deg b)ii) Hence the angle of inclination is 18.4 deg
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