標題:
有數唔識(a.maths)
1) log 8 + log √32 / log 4 2) log 5 + 2log2 - 1 / 2log4 - log0.5
最佳解答:
1) (log8 + log√32) / log4 = (log23 + log321/2) / log22 = (log23 + log 25/2) / log22 = [3 log2 + (5/2)log 2] / 2log2 = (11/2)log2 / 2log2 = (11/2)/2 = 11/4 2) (log5 + 2log2﹣1) / (2log4﹣log0.5) =( log 5 + log4﹣log 10) / (log 16﹣log 0.5) = (log20﹣log10) / (log32) = log2 / log32 = log2 / (log25) = log2/(5 log2) = 1/5 2008-01-29 19:09:04 補充： logM^n = n log M√x = x^1/2log10 = 1
其他解答:
有數唔識(a.maths)
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發問:1) log 8 + log √32 / log 4 2) log 5 + 2log2 - 1 / 2log4 - log0.5
最佳解答:
1) (log8 + log√32) / log4 = (log23 + log321/2) / log22 = (log23 + log 25/2) / log22 = [3 log2 + (5/2)log 2] / 2log2 = (11/2)log2 / 2log2 = (11/2)/2 = 11/4 2) (log5 + 2log2﹣1) / (2log4﹣log0.5) =( log 5 + log4﹣log 10) / (log 16﹣log 0.5) = (log20﹣log10) / (log32) = log2 / log32 = log2 / (log25) = log2/(5 log2) = 1/5 2008-01-29 19:09:04 補充： logM^n = n log M√x = x^1/2log10 = 1
其他解答:
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